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Mathematics 19 Online
OpenStudy (anonymous):

Anyone know the correct answer? Attachment.

OpenStudy (anonymous):

OpenStudy (anonymous):

In this case you could use the quadratic formula to solve for x

OpenStudy (anonymous):

you might attempt completing the square too

OpenStudy (anonymous):

i got something like x= 1/2(-9-\[\sqrt{85}\] x=1/2 (\[\sqrt{85}\]-9)

OpenStudy (anonymous):

Lol minus the huge gaps

OpenStudy (anonymous):

\[x = -b \pm\ \frac{\sqrt{b^2 - 4* a * c}}{2a}\]

OpenStudy (anonymous):

a = 1, b = 9, c = -1

OpenStudy (anonymous):

Sorry, I'm just working it out

OpenStudy (anonymous):

It's ok

OpenStudy (anonymous):

Fine by me

OpenStudy (anonymous):

\[x = \frac{-b \pm\ \sqrt{b^2 - 4* a * c}}{2a}\]

OpenStudy (anonymous):

OK, \[x = \frac{-9 \pm\ \sqrt{9^2 - 4* 1 * (-1)}}{2*1}\] = \[x = \frac{-9 \pm\ \sqrt{85}}{2}\]

OpenStudy (anonymous):

so \[x = (1/2)(-9 - \sqrt{85})\] and \[x = (1/2)(-9 + \sqrt{85})\]

OpenStudy (anonymous):

so you got it!

OpenStudy (anonymous):

Aha, ok :) Thanks a lot

OpenStudy (anonymous):

thanks, any more questions?

OpenStudy (anonymous):

Umm... Am I sposed to write that a certain way?

OpenStudy (anonymous):

no, you could try simplifying the radical, \[\sqrt{85}\]

OpenStudy (anonymous):

I just didn't know if i was sposed to write it in {} or something.

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