Mathematics
10 Online
OpenStudy (anonymous):
Anyone know the correct answer? Attachment.
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OpenStudy (anonymous):
OpenStudy (anonymous):
In this case you could use the quadratic formula to solve for x
OpenStudy (anonymous):
you might attempt completing the square too
OpenStudy (anonymous):
i got something like
x= 1/2(-9-\[\sqrt{85}\]
x=1/2 (\[\sqrt{85}\]-9)
OpenStudy (anonymous):
Lol minus the huge gaps
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OpenStudy (anonymous):
\[x = -b \pm\ \frac{\sqrt{b^2 - 4* a * c}}{2a}\]
OpenStudy (anonymous):
a = 1, b = 9, c = -1
OpenStudy (anonymous):
Sorry, I'm just working it out
OpenStudy (anonymous):
It's ok
OpenStudy (anonymous):
Fine by me
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OpenStudy (anonymous):
\[x = \frac{-b \pm\ \sqrt{b^2 - 4* a * c}}{2a}\]
OpenStudy (anonymous):
OK, \[x = \frac{-9 \pm\ \sqrt{9^2 - 4* 1 * (-1)}}{2*1}\] = \[x = \frac{-9 \pm\ \sqrt{85}}{2}\]
OpenStudy (anonymous):
so \[x = (1/2)(-9 - \sqrt{85})\] and \[x = (1/2)(-9 + \sqrt{85})\]
OpenStudy (anonymous):
so you got it!
OpenStudy (anonymous):
Aha, ok :) Thanks a lot
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OpenStudy (anonymous):
thanks, any more questions?
OpenStudy (anonymous):
Umm... Am I sposed to write that a certain way?
OpenStudy (anonymous):
no, you could try simplifying the radical, \[\sqrt{85}\]
OpenStudy (anonymous):
I just didn't know if i was sposed to write it in {} or something.