Question

Partial fraction? nope. U-sub? Nope. Uhhhh...
http://www.wolframalpha.com/input/?i=int%3A+%287-x%29%2F%28x^3-2x^2-x-2%29

Answer 1

Any ideas on how to solve this?

Answer 2

Maybe if I factor an x^2 from the bottom?

Answer 3

no i dont think that gets me anywhere...

Answer 4

x^3 -2x^2 -x -2

(x^3-x)+(-2x^2 -2)

x(x^2-1) -2(x^2 +1) hmmm

Answer 5

amistreee! helpp meee:(

Answer 6

are there any limits of integration that you are omitting bychance?

Answer 7

Nope, it is indefinite.

Answer 8

well, i do know that the majority of integrations cannot be done using elementary functions; the textbooks lull you into a false sense of security with it :)

Answer 9

What the heck does the wolfram answer even mean??

Answer 10

dunno, i think you broke it :)

Answer 11

lol

Answer 12

im pretty sure if the wolf came up with that, there aint gonna be an easy answer ....

Answer 13

Yea ughh

Answer 14

I'll hit up math stack exchange

Answer 15

Zarkon, Myininaya, what do you 2 think? impossible?

Answer 16

doesn't look good. I've used 3 different programs and none of them can find the explicit antiderivative

Answer 17

Ok thanks

Answer 18

i got gibberish

sum((_R-7)*ln(x-_R)/(3*_R^2-4*_R-1), _R = RootOf(_Z^3-2*_Z^2-_Z-2))

Answer 19

spose we could come up with an appropriate power series for it?

Answer 20

if you don't care about having the exact roots you can get approximate roots...

http://www.wolframalpha.com/input/?i=int%3A+%287.0-x%29%2F%28x^3-2x^2-x-2%29

Answer 21

Mathematica uses Root objects to represent the solutions where u can't get algebraic expressions.

Then u have to do numerically like Zarkon says.