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Integrate e^x/(1+e^(2x)) using substitution?
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looks like \[\int\frac{u}{1+u^2}du\]
Ahh, that was pretty easy! Been at this a little too long I think. Thanks!
anti derivative is \[\frac{1}{2}\ln(u^2+1)\]
i mean you still have to make the substitution yes?
well, yeah, but I was having a hard time figuring out the form. From there it would be inverse tan(e^x)+C, correct?
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wait wait
i steered you wrong. you have it. right exactly
\[u=e^x\] etc. you get \[\tan^{-1}(u)=\tan^{-1}(e^x)\]
Thanks for the help!
latex all messed up
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yw
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