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Mathematics 19 Online
OpenStudy (anonymous):

xy(x/y+y/x)

OpenStudy (anonymous):

What are we doing with this?

OpenStudy (anonymous):

simplify

OpenStudy (anonymous):

multiply top and bottom by xy

OpenStudy (anonymous):

k

OpenStudy (anonymous):

i may have read it wrong. is it just \[xy(\frac{x}{y}+\frac{y}{x})\]

OpenStudy (anonymous):

if it is answer is \[x^2+y^2\]

OpenStudy (anonymous):

ur right

OpenStudy (anonymous):

i guess

OpenStudy (anonymous):

but how?

OpenStudy (anonymous):

thats wat i wanted to know

OpenStudy (anonymous):

distributive law \[xy\times \frac{x}{y}=\frac{xyx}{y}=x^2\]

OpenStudy (anonymous):

since multiplying means multiply in the numerator, and the y in the numerator cancels with the y in the denominator

OpenStudy (anonymous):

likewise \[xy\times \frac{y}{x}=\frac{xyy}{x}=y^2\]

OpenStudy (anonymous):

thx

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