A population grows according to the equation P(t) = 6000 - 5500e^-.159t for t is greater than or equal to 0, t in years. This population will approach a limiting value as time goes on. During which year will the population reach half this limiting value?

Question

A population grows according to the equation P(t) = 6000 - 5500e^-.159t for t is greater than or equal to 0, t in years.  This population will approach a limiting value as time goes on.  During which year will the population reach half this limiting value?

anonymous · Answer

3.81 years

anonymous · Answer

explanation?

anonymous · Answer

limiting value is 6000  so half its value is 3000
therefore p=3000 and solve

anonymous · Answer

i got to .545 = e^-.519t?  I dont now how to go further

anonymous · Answer

yes  use logerithms on both sides and solve  dude

anonymous · Answer

right.  sorry its been a while since ive done logs

anonymous · Answer

apply log 2 the base e

anonymous · Answer

my medal dude  !!!!!!!!

anonymous · Answer

so... its safe to say in the 4th year?

anonymous · Answer

yup  !!!!!!!!