Find the area of the shaded portion in the equilateral triangle with sides 6.
(assuming the central point of each arc is its corresponding vertex)
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OpenStudy (anonymous):
OpenStudy (anonymous):
btw its not a thong soo no ideas!!
OpenStudy (saifoo.khan):
Lol @ thongs.
OpenStudy (saifoo.khan):
\[\Huge Hasirrrr!\]
OpenStudy (anonymous):
yup i m here
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OpenStudy (anonymous):
apply sine rule
a=1/2(6)(6)sin60 then
OpenStudy (saifoo.khan):
aera of triangle = 7.8
OpenStudy (anonymous):
find area of sector A of sector= (60/360)(pie)(3)^2
multiply it by three
OpenStudy (anonymous):
subrat it from the A u get from the sine rule
OpenStudy (saifoo.khan):
lol, im getting 3 different answers!
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OpenStudy (anonymous):
apply sine rule
a=1/2(6)(6)sin60 then
find area of sector A of sector= (60/360)(pie)(3)^2
multiply it by three
ans=15.58-3(4.71)=1.443
OpenStudy (anonymous):
hey hello saif
OpenStudy (saifoo.khan):
lol, hi honey.. supp?
OpenStudy (anonymous):
nm u?
OpenStudy (saifoo.khan):
same here, nm.
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OpenStudy (anonymous):
hi..........saif i solved the question koi medal to do
OpenStudy (anonymous):
Looks like 3 sectors of a circle.
Area of a sector of a circle is: area of circle * degrees of sector/360
the sector has 60 degrees because the triangle is equilateral.
Area of circle = 9π
Area of 3 sectors: 9π * 60/360 * 3 = 4.5π
Area of shaded part = area of triangle - 4.5π
area of triangle = 1/2(6)(6)(sin 60) = 15.5884573
4.5π = 14.1371669
15.5884573 - 14.1371669 = 1.4512904
Hope that helps
OpenStudy (anonymous):
ummm guys u know that theres a thing cxalled group chat below ur screen lolz
OpenStudy (anonymous):
sorry terr this is more coool
OpenStudy (saifoo.khan):
Lol @ terri & honey!
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