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Mathematics 7 Online
OpenStudy (anonymous):

Find the area of the shaded portion in the equilateral triangle with sides 6. (assuming the central point of each arc is its corresponding vertex)

OpenStudy (anonymous):

OpenStudy (anonymous):

btw its not a thong soo no ideas!!

OpenStudy (saifoo.khan):

Lol @ thongs.

OpenStudy (saifoo.khan):

\[\Huge Hasirrrr!\]

OpenStudy (anonymous):

yup i m here

OpenStudy (anonymous):

apply sine rule a=1/2(6)(6)sin60 then

OpenStudy (saifoo.khan):

aera of triangle = 7.8

OpenStudy (anonymous):

find area of sector A of sector= (60/360)(pie)(3)^2 multiply it by three

OpenStudy (anonymous):

subrat it from the A u get from the sine rule

OpenStudy (saifoo.khan):

lol, im getting 3 different answers!

OpenStudy (anonymous):

apply sine rule a=1/2(6)(6)sin60 then find area of sector A of sector= (60/360)(pie)(3)^2 multiply it by three ans=15.58-3(4.71)=1.443

OpenStudy (anonymous):

hey hello saif

OpenStudy (saifoo.khan):

lol, hi honey.. supp?

OpenStudy (anonymous):

nm u?

OpenStudy (saifoo.khan):

same here, nm.

OpenStudy (anonymous):

hi..........saif i solved the question koi medal to do

OpenStudy (anonymous):

Looks like 3 sectors of a circle. Area of a sector of a circle is: area of circle * degrees of sector/360 the sector has 60 degrees because the triangle is equilateral. Area of circle = 9π Area of 3 sectors: 9π * 60/360 * 3 = 4.5π Area of shaded part = area of triangle - 4.5π area of triangle = 1/2(6)(6)(sin 60) = 15.5884573 4.5π = 14.1371669 15.5884573 - 14.1371669 = 1.4512904 Hope that helps

OpenStudy (anonymous):

ummm guys u know that theres a thing cxalled group chat below ur screen lolz

OpenStudy (anonymous):

sorry terr this is more coool

OpenStudy (saifoo.khan):

Lol @ terri & honey!

OpenStudy (saifoo.khan):

@hashir, a medal for a medal..

OpenStudy (anonymous):

i think u have one

OpenStudy (saifoo.khan):

i have two!

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