Question

State the solution in interval notation: x^2+5x-6<0. Can anyone help me with this problem?

Answer 1

oh my dearest saifoo
there is no such thing as
\[-6>x<1\] that number does not exist

Answer 2

ahhh, where the hell am I?
Im sleeping, lol.

Answer 3

also this line
\[x<1\]
\[x<-6\] is also wrong. you need a break

Answer 4

Lol.

Answer 5

answer is right though!

Answer 6

please solve it satellite.

Answer 7

Yes, please help. I have a final in a half hour and I can't figure this one out.

Answer 8

@tburn

\[y=x^2+5x-6\] is a parabola that faces up. it has zeros at
\[x=-1,x=6\] and by the picture (in your head) since this is a parabola that faces up with those zeros it must be negative between them. so your answer is
\[(-1,6)\] just as saifoo said. it is his method that makes no sense

Answer 9

sorry that is wrong. zeros at
\[x=-6,x=1\] so negative ono
\[(-6,1)\]

Answer 10

i had the zeros backwards. here is a picture and you can see
http://www.wolframalpha.com/input/?i=y%3Dx^2%2B5x-6

Answer 11

negative just means below the x - axis

Answer 12

also you should understand that when you solve
\[x^2+5x-6<0\] you are really solving for everything. less that zero, greater than zero as well since it is either one or the other

Answer 13

In my problem you also have to solve using a sign graph.

Answer 14

well you mean with the little pluses and minuses?

Answer 15

x+6 ------- [-6]++++++++++++++++++
x-1 ----------------------------[1]++++++

(x+6)(x-1) ++++++-6------------------1+++++++++++

Answer 16

there negative between the zeros and positive outside them
but you are not a moron, you are allowed to think. parabola faces up, negative between the zeros, positive outside them
parabola faces down, then positive between the zeros. this is a dumb method