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Mathematics 23 Online
OpenStudy (anonymous):

Simplify the following...

OpenStudy (anonymous):

\[\frac{5}{x^2+5x+6}+\frac{2}{x+3}\]

OpenStudy (anonymous):

um sorry, I myself is confused :S

OpenStudy (anonymous):

It's cool. Whoever does get it, please show your steps.

OpenStudy (anonymous):

2X+9/(X+3)(X+2)

OpenStudy (anonymous):

How did you get that?

OpenStudy (amistre64):

you factor the left side there into something withe a (x+3) in it .... since that is really the most obvious option; unless your math program has gone sadistic on you like mathLab does :)

OpenStudy (anonymous):

\[\frac{5}{x^2+5x+6}+\frac{2}{x+3}\] manipulate the denominator on the first term to be \[x^2+5x+6 = (x+3)(x+2)\] then you have \[\frac{5}{(x+3)(x+2)}+\frac{2}{x+3}\] now you need to find the common denominator of both terms, this would be \[(x+3)(x+2)\] therefore you need to multiply the 2nd term by 1, where 1 is \[(x+2)/(x+2)\] yielding \[\frac{5}{(x+3)(x+2)}+\frac{2}{x+3} * \frac{(x+2)}{(x+2)}\] = \[ \frac{5}{(x+3)(x+2)}+\frac{2(x+2)}{(x+3)(x+2)}\] now you can focus on the numerator and combine the two: \[5 + 2x+4=2x+9\] so you have \[\frac{2x+9}{(x+3)(x+2)}\]

OpenStudy (anonymous):

Thanks :D

OpenStudy (anonymous):

no problem, was this clear?

OpenStudy (anonymous):

Very!

OpenStudy (anonymous):

cool, anymore questions?

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