Part 1: Explain, in complete sentences, how you would use the graphing method to solve the following system of equations. (3 points) Part 2: Provide the solution to the system. (2 points) Part 3: Explain what the solution represents on the graph. (1 point) 3x – 6y = 12 9x + 2y = –24
i wouldnt use the graphing method to solve any system of equations; id simply use it as a visual aid to get me in the ballpark
Geometry without algebra is dumb (ask the Greeks), algebra without geometry is blind (ask the Chinese).
could somebody just help me learn to graph it
do you need all the points of each equation? or will just 2 for each one work?
Ok, we just want to know whether u are expected to do it all by graph only.
I have to do it all by graph. and two for each one will work!
just explain how to graph it.... then help me solve the system....and explain how the solution represents the graph
which 2 points do you think will be the easiest to find with these equations?
2 points for each equation that is
Do u know that they are straight lines?
yes they are straight lines. @amistre64 and a point on the x axis and a point on the y axis?
correct :) so we use x=0 in one case; and y=0 in the other and that should give us 2 points to draw a line with right?
3x – 6y = 12 ; (x=0, y=?) ; (x=? , y=0)
how would we solve the ? do you have to solve the 3x-6y=12 twice one time for y and another time for x?
yes
the equation is a road map; use it as many times as you need.
(x=0, y=-2) ; (x=-3/-6 , y=0) is that it? im not quite sure
if your not sure; how can we chk to make sure?
plug it into the equation?
thats right; your second point there is not going to fit into the equation very well, you might want to rethink it ..
x=2y+4 so.... (x=0, y=-2) ; (x=4 , y=0)
thats better :) now we can omit the "x=" and the "y=" parts to get our points looking like normal
yes then we graph them....and are those points also the the solutions to the equation?
those points are just solutions to ONE of the equations, namely the top equation.
connect the points with a line that continues thru them
oh okay. so 9x + 2y = –24; (x=0, y=12) ; (x=? , y=0). but when i solve for x 9 dosnt go into 24 so what would I do?
your first point should be (0,-12) by the way fractions are fractions ... you best bet for an integer would be to solve for x in such a way that you can see an integer in it ... 9x + 2y = -24 ; -2y 9x = -24 - 2y ; /9 x = (-24 - 2y)/9 ;factor out a -1 x = -1 (24 + 2y)/9 now what numbers do 9 go into that we can make out of 24 + 2y ? 24 + 2(0) = 24 24 + 2(1) = 26 24 + 2(2) = 28 24 + 2(3) = 30 24 + 2(4) = 32 24 + 2(5) = 34 24 + 2(6) = 36 .. heres one ; 9(4) = 36 too so lets try this with y= 6 x = -1* (24 + 2(6))/9 = -1* 36/9 = -1* 4 = -4 ; (-4,6) looks like a good spot
then for the solution i just find which point lies on both lines (intersection)
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