Question

How do you solve this summation?

Answer 1

\[\sum_{d=0}^{\infty}50(1/10)^{d}\]

Answer 2

its a geometric series.

Answer 3

you can factor the 50 out:
\[50\sum_{d=0}^{\infty}\frac{1}{10}^d\]

Answer 4

yep : ) infinite one
\[Sum = \frac{a}{1 -r}\]

Answer 5

then the formula for an infinite geometric series is what ishaan posted, where a is the first term (which will be a 1 from where i left off), and r = 1/10

Answer 6

So a is 50

Answer 7

yeah. i guess i could have left the 50 in there.

Answer 8

and then r will be 1/10 so 1-(1/10) = 9/10

Answer 9

so:
\[\frac{50}{1-\frac{1}{10}}\]

Answer 10

right right, you got it :)

Answer 11

soooo 50/9/10 = 500/9

Answer 12

Thanks! I understand now!

Answer 13

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