Question

What is the distance formula?

Answer 1

\[\sqrt{(x2 - x1)^{2}+ (y2 - y2)^{2}}\]

Answer 2

aka Pythagorus

Answer 3

Okay, as a future math teacher, I say DON'T MEMORIZE THE DISTANCE FORMULA.

Answer 4

Memorize the pythagorean formula and be able to apply it. Every distance problem is just a pythagoras problem in disguise.

Answer 5

U can have as many "distance formulas" as u want (then they are called "metrics"

Answer 6

You just have to notice that it's a right triangle with 1 leg equal in length to the x difference between the two points and 1 leg with length equal to the y difference.

Answer 7

I looked it up..in my textbook and online.

Answer 8

OK, what's the distance formula in 3D?

Answer 9

I think u need to improve your online research skills.

Answer 10

http://en.wikipedia.org/wiki/Distance_formula#Geometry

Here are some "distance formula"

Answer 11

They only gave one formula in my textbook, and I DONT TRUST WIKIPEDIA.

Answer 12

Oh, well that's alright, then...:-)

Answer 13

I can show you on twiddle

Answer 14

somebody tell me the stupid formula

Answer 15

Refer to the picture. There's your formula.

Answer 16

Distance formula in 3D should be

Let the Co-Ordinates be (x,y,z)
then on respective co-ordinate axes
(0,0,z) , (0,y,0) and (x,0,0)

First I would Solve the x-z Plane

Which should be \[\sqrt{x^2 + z^2}\]

Then Apply Pyth. Theorem which sould be \[\sqrt{x^2 + y^2 + z^2}\]

I tried to Derive it ...took a lot of time
it is of a point ditance from origin

So, Using my Derivation

For two points \[x_1 , y_1, z_1\] and \[x_2, y_2, z_2\]

So...the distance formula turns out

\[ Distance = \sqrt{ (x_2 - x_1)^2 + (y_2 - y_1)^2 + (z_2 - z_1)^2}\]
I know it took a lot of time ...but I did this to satisfy my Intellect...If you spot some error then Please do tell me .

Answer 17

here it is. i dont know how i memorized this.
d=sqrt{(x-x)^2 + (y-y)^2}