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Mathematics 22 Online
OpenStudy (anonymous):

Find that probability that a point chosen at random in the figure lies in the Green circle. The Green Circle has a diameter of 24. (The Green Circle is in the Blue Square)

OpenStudy (amistre64):

its like reading bedtime stories to the blind :)

OpenStudy (anonymous):

lol

OpenStudy (amistre64):

im gonna assume the circle is inscribed in the square ... the prob will be: area.circle/area.square

OpenStudy (anonymous):

The diameter of the circle will be the diagonal of the square.

OpenStudy (amistre64):

"side" i think

OpenStudy (amistre64):

OpenStudy (anonymous):

Oh, bah. I thought the square was inscribed in the circle, not the other way around..

OpenStudy (anonymous):

My way was much more interesting.

OpenStudy (anonymous):

Also, I don't think you need the diameter.

OpenStudy (amistre64):

diam is just for making the area of the square easier to obtain ..

OpenStudy (anonymous):

i know how to find the area of the circle but im not sure how to find the area of the square

OpenStudy (anonymous):

\[Area_\square = s^2\]\[Area_\bigcirc = \pi r^2 = \pi (\frac{s}{2})^2 = \frac{1}{4}\pi s^2\] \[Probability =\frac{Area_\bigcirc}{Area_\square}\]

OpenStudy (anonymous):

It's not needed to know the diameter, the s factors cancel.

OpenStudy (anonymous):

The area of a square is the length of the side squared.

OpenStudy (anonymous):

The length of the side is the diameter of the circle.

OpenStudy (anonymous):

So given that the s factors cancel we can tell that it doesn't matter how big the circle is, the probability will always be the same given this arrangement.

OpenStudy (anonymous):

i keep getting 21.5% but its not the right answer

OpenStudy (anonymous):

Did you do what I wrote above?

OpenStudy (anonymous):

\[Probability =\frac{Area_\bigcirc}{Area_\square} = \frac{\frac{1}{4}\pi s^2}{s^2} = \frac{\pi}{4}\]

OpenStudy (anonymous):

yea...i think so at least. but im not sure why in order to find the area of a circle you need 1/4?

OpenStudy (anonymous):

The area of the circle is \(\pi r^2\). But the r is the diameter divided by 2. The diameter is also the length of one side of the square.

OpenStudy (anonymous):

So I wrote my r as being \(\large\frac{s}{2}\)

OpenStudy (anonymous):

and when I squared that I got \(\large \frac{s^2}{4}\)

OpenStudy (anonymous):

yea i know all of that and this is my equation when i do p r^2 576-452.16/576=123.84/576=0.215 and move the decimal 2 places and get 21.5%

OpenStudy (anonymous):

This is why calculators are bad ;p

OpenStudy (anonymous):

where is that 576 from?

OpenStudy (anonymous):

that's the area of the square?

OpenStudy (anonymous):

Oh I see what the problem is.

OpenStudy (anonymous):

You have the right value for the areas. You just subtracted them for some reason.

OpenStudy (anonymous):

The probability will be the area of the circle divided by the area of the square

OpenStudy (anonymous):

no need to subtract

OpenStudy (anonymous):

\[\frac{452.16}{576} \approx \frac{\pi}{4} \approx78.54\%\]

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