Question

find the critical numbers,

g(t)=t*sqrt(1-t), t<1

pleas ehelp me on this one guys, and i forgot the last perosn who helped me but thank yous so much..my comp froze:S

Answer 1

hey

Answer 2

g'(t) = sqrt(1-t) - t/2sqrt(1-t)
We'll put g'(t) = 0
sqrt(1-t) - t/2sqrt(1-t) = 0
2(1-t) - t = 0
2 - 2t - t = 0
-3t = -2
t = 2/3
critical number t = 2/3

Answer 3

thank you so much!!!:)

Answer 4

\[g'(t)=(2-3t)/2(1-t)^{1/2}\]
critical values are \[2-3t =0\]
and \[2(t-1)^{1/2}=0\]
thus, t= 1 and t=2/3