Question

Identify the open intervals on which the function is increasing or decreasing.
h(x) = 3x − x3


how do i do this

Answer 1

find h'(x), then set h'(x) = 0. That will give you the critical points. Then, create a number line. Place the critical points on the number line. Evaluate h'(x) between the intervals. If h'(x) is positive, then h(x) is increasing. If h'(x) is negative, then h(x) is decreasing.

Answer 2

You keep re-posting the same question even when someone is trying to help;Good luck getting someone to help you.

Answer 3

x= -1 or x= 1
thats what i got so far

Answer 4

x= -1 or x= 1
thats what i got so far

Answer 5

x= -1 or x= 1
thats what i got so far

Answer 6

x= -1 or x= 1
thats what i got so far

Answer 7

x= -1 or x= 1
thats what i got so far

Answer 8

x= -1 or x= 1
thats what i got so far

Answer 9

x= -1 or x= 1
thats what i got so far

Answer 10

x= -1 or x= 1
thats what i got so far

Answer 11

x= -1 or x= 1
thats what i got so far

Answer 12

WoW

Answer 13

You only need to post once, lol

Answer 14

http://openstudy.com/users/lostdove#/users/lostdove/updates/4e31a6b60b8ba7b2da411efa

Answer 15

So x = (-1,1) is your critical points.....Now plot them on a number line and evaluate h'(x) at a point between intervals (-infinity,-1), (-1,1) and (1,infinity).

Answer 16

lo sorry about that. i am desperate for help. lol im being timed so i needed help like asap and im soo confused. but i got the critical number but idk which option to pick

Answer 17

Let me know what you get

Answer 18

Another thing you can do is graph it....you already know the critical points now....

Answer 19

so is it increasing from 1 to infinity?
and decreasing from -infinity to -1 ?

Answer 20

Correct. But what about between -1,1 ?

Answer 21

Use .5 as x

Answer 22

or even 0

Answer 23

okay

Answer 24

What do you get? Also, to check your answer, just graph it