Ask your own question, for FREE!
Mathematics 21 Online
OpenStudy (anonymous):

I need to factor 3x^3-5x^2+9x-15

OpenStudy (lalaly):

(3x^2 - 5)( x^2 +3)

OpenStudy (anonymous):

How did you get that?

OpenStudy (anonymous):

u have to kinda move them around so its 3x^3+9x-5x^2-15

OpenStudy (anonymous):

then you group them

OpenStudy (anonymous):

Oh, ok

OpenStudy (anonymous):

so the first part is 3x^3+9x which is the same as 3x(x^2+3)

OpenStudy (anonymous):

then the second part is 5x^2-15 so its 5(x^2-3)

OpenStudy (anonymous):

sorry that second part should be 5(x^2+3)

OpenStudy (anonymous):

since they both have x^2+3, you combine them to make (3x-5)(x^2+3)

OpenStudy (anonymous):

make sense?

OpenStudy (anonymous):

From my math book, so far I have x[3(x^2)-5(x^2+3)]

OpenStudy (anonymous):

Oops, let me re-write that, I made a mistake

OpenStudy (anonymous):

x[3(x^2+3x)-5(x^2+3)]

OpenStudy (anonymous):

I did that wrong too! I'm so messed up and confused, sorry

OpenStudy (anonymous):

well for the 3(x^2+3x) you can take out another x so it can be 3x(x+3)

OpenStudy (anonymous):

also i dont think there should be an x on the outside of the bracket

OpenStudy (anonymous):

so does 3x(X^2+3)-5(x^2+3) look right?

OpenStudy (anonymous):

Actually, it does!

OpenStudy (anonymous):

good.. then ur on the right track

OpenStudy (anonymous):

since both parts have x^2+3, you can take that term out

OpenStudy (anonymous):

leaving (x^2+3)(3x-5)

OpenStudy (anonymous):

which is the answer

OpenStudy (anonymous):

Thank you so much! You ARE a lifesaver!

Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!
Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!