Mathematics
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OpenStudy (anonymous):
I need to factor 3x^3-5x^2+9x-15
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OpenStudy (lalaly):
(3x^2 - 5)( x^2 +3)
OpenStudy (anonymous):
How did you get that?
OpenStudy (anonymous):
u have to kinda move them around
so its 3x^3+9x-5x^2-15
OpenStudy (anonymous):
then you group them
OpenStudy (anonymous):
Oh, ok
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OpenStudy (anonymous):
so the first part is 3x^3+9x which is the same as 3x(x^2+3)
OpenStudy (anonymous):
then the second part is 5x^2-15 so its 5(x^2-3)
OpenStudy (anonymous):
sorry that second part should be 5(x^2+3)
OpenStudy (anonymous):
since they both have x^2+3, you combine them to make (3x-5)(x^2+3)
OpenStudy (anonymous):
make sense?
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OpenStudy (anonymous):
From my math book, so far I have x[3(x^2)-5(x^2+3)]
OpenStudy (anonymous):
Oops, let me re-write that, I made a mistake
OpenStudy (anonymous):
x[3(x^2+3x)-5(x^2+3)]
OpenStudy (anonymous):
I did that wrong too! I'm so messed up and confused, sorry
OpenStudy (anonymous):
well for the 3(x^2+3x) you can take out another x so it can be 3x(x+3)
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OpenStudy (anonymous):
also i dont think there should be an x on the outside of the bracket
OpenStudy (anonymous):
so does 3x(X^2+3)-5(x^2+3) look right?
OpenStudy (anonymous):
Actually, it does!
OpenStudy (anonymous):
good.. then ur on the right track
OpenStudy (anonymous):
since both parts have x^2+3, you can take that term out
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OpenStudy (anonymous):
leaving (x^2+3)(3x-5)
OpenStudy (anonymous):
which is the answer
OpenStudy (anonymous):
Thank you so much! You ARE a lifesaver!