Find the area bounded region between the curve y=x^3-6x^2+8x and the x axis.

Question

anonymous · Answer

well, the first thing you must do is find the limits of integration. To do this set both curves equal to each other and solve for x

anonymous · Answer

http://www.wolframalpha.com/input/?i=y%3Dx^3-6x^2%2B8x Heres the graph

anonymous · Answer

The Curve intersects x- axis at 0 , 2 and 4

anonymous · Answer

this is actually pretty good graph, cause we have what is called symmetry

anonymous · Answer

to find out the area ...all you need to do is 

INTEGRATION 

$$Area  = \int\limits _{0}^{2} f(x)dx + \int\limits_{2}^{4} f(x)dx$$
thats all you should do good luck : )

anonymous · Answer

I don't know the equation tool has some problem it doesn't show the integration sign

anonymous · Answer

and yeah even if one of the area comes negative, you make it positive ...because area can't be negative

anonymous · Answer

oh okay.thats why i got a 0 instead for my answer.my negative part of answer and posirive part cancel out each other.thanks!!

anonymous · Answer

okay i got you ....good : )