Question

Really need help solving this step by step. I know the answer is 2 but i dont know how to get the answer by doing it on paper
2√+6√2+3√−−−−−−√

Answer 1

uber,what about me?

Answer 2

\[\frac{\sqrt{2}+\sqrt{6}}{\sqrt{2+\sqrt{3}}}\]

Answer 3

@Cali: There's enough uber to go around for everyone. :P

Answer 4

@Courtney: Just to double check:
"Square root of 2 plus square root of 6, all divided by square root of 2 plus square root of 3", right?

Answer 5

\[\frac{\sqrt{2}+\sqrt{6}}{\sqrt{2+\sqrt{3}}}\]

Answer 6

correct! ive been trying to figure it out but it's taking me FOREVER

Answer 7

You need to multiply by the conjugate.

\[(\sqrt{2}+\sqrt{6}\div \sqrt{2}+\sqrt{6})\times(\sqrt{2}-\sqrt{6}\div \sqrt{2}-\sqrt{6})\]

Solve this and you should get your answer

Answer 8

chaise-would you do the \[\sqrt{6}\div \sqrt{2} \] first?

Answer 9

Multiply the numberators together, multiply the denominators together.

Answer 10

would you mind showing me step by step because i honestly dont remember a lot about the rules of square roots and stuff

Answer 11

When you multiply by the conjugate you are not changing the answer. When you multiply by sqrt 2 - sqrt 6/sqrt - sqrt 6 (which is equal to 1, any number divded by itself is 1) you are not changing the answer. I dont know how to type to explain it. Do you want to join me here so I can explain?

http://www.twiddla.com/583170

Answer 12

Courtney: I was going to tell you that the conjugate is the opposite addition/subtraction of the denominator. So, if it says (y+x), the conjugate is (y-x). So, just do what chaise said, but be sure you know how to find conjugates for future reference.

Answer 13

so you can still do the conjugate thing even though the denominator has a square root over the whole thing?

Answer 14

uber??

Answer 15

do you have the answers choices?

Answer 16

(sqrt2+sqrt6)(sqrt(sqrt2-sqrt3))=sqrt2(sqrt(sqrt2+sqrt3))+sqrt6(sqrt(sqrt2-sqrt3))

Answer 17

no i dont