Find the area of the shaded portion in the circle. click pic below
what would the entire area of the circle be?
or rather, do you recall the formula for the area of a circle?
and are we allowed to use trig? cause that top half is looking a little intimidating :)
the angle, formed for the segment, if i did it right; is cos-1(-4/9)
entire area is good to know; but i spose we could do it in parts
or by complements; determin the white area and subtract it from the whole
I would probably go about using simpson's rule for this one... Personally, seems easiest and somewhat accurate.
i dont think her class is into the simpsons rule; unless im confusing the calculus one for something else ...
if we form a right triangle; with hyp = 6 and leg = 3 we get a base of sqrt(27) the triangle up top then has a base of 2sqrt(7) and a height of 3 giving us an area of 3sqrt(27); then we need to determine the side segments
Simpson's rule isn't overly difficult. Simspon's rule is.. w/3(x+2E+4O)? Correct me if I'm wrong? Split the circle into equal distances of say.. 0.5 and then use simpson's rule..
i couldnt tell you if that would be right or wrong :) cant remember that far back ...
Seems logical, I can't be too sure either. (0.5/3)((2x3) + (2x11x3) + (4x11x3)) Does this sound right, I couldn't be too sure.
the angle I see formed for the side segments area is: tan-1(3/sqrt(27)) to wit: area = 6^2 sin(a)/2 ; and 2 sides makes it .... 6^2 sin(a) 36 sin(tan^(-1)(3/sqrt(27))) = 18 really? that was cool total circle - (3sqrt(27) + 18) if i did it right :)
total area = 36pi ... maybe so 36pi -(3sqrt(27)+18) =abt. 102.5 pi
...... that doesnt make sense lol .... the area would be greater than the whole :)
79.5 would be better if I did it right; but that includes the pi .... so I tried to divide it out and get: abt 25pi :)
is there any way to determine if we got it right? or is there a certain degree of accuracy you are going for?
http://www.wolframalpha.com/input/?i=%2836pi+-%283sqrt%2827%29%2B18%29%29%2Fpi forgot a paranthesis :) 25.308... pi is my best guess
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