Ask
your own question, for FREE!
Mathematics
3 Online
OpenStudy (anonymous):
What is the equation of the axis of symmetry for the function shown below?
y-2=-(x+5)^2
A. x = -5
B. x = 5
C. y = 2
D. x = 2
Join the QuestionCove community and study together with friends!
Sign Up
OpenStudy (anonymous):
The axis of symmetry goes through the vertex vertically.
OpenStudy (anonymous):
This equation is in vertex form. Can you tell what the vertex is?
OpenStudy (anonymous):
(5,-2)
OpenStudy (anonymous):
Close!
(-5,2) actually.
OpenStudy (anonymous):
Recall that vertex form is:
\[y-k = C(x-h)^2\]
Where (h,k) is the vertex.
Join the QuestionCove community and study together with friends!
Sign Up
OpenStudy (anonymous):
So your version:
y-2=-(x+5)^2
Is equivalent to:
y - 2 = -1(x-(-5))^2
Therefore h = -5, and k = 2
So (-5,2) is the vertex.
OpenStudy (anonymous):
Now, what is the equation of a line that is vertical (up and down) that goes through (-5,2)
OpenStudy (anonymous):
y=2
OpenStudy (anonymous):
y = 2 is a horizontal line that goes through the y axis at y = 2.
OpenStudy (anonymous):
a vertical line has the form x = h where h is the point on the x axis that the line intersects.
Can't find your answer?
Make a FREE account and ask your own questions, OR help others and earn volunteer hours!
Join our real-time social learning platform and learn together with your friends!
Latest Questions
clllaaaaaire:
CLOSED
2 weeks ago
0 Replies
0 Medals