I dentify the solution for 2x^2+1< 9x-3
\[2x^2-9x+4<0\] is a start
Then?
OIC,
\[(x-4)(2x-1)<0\]
So, x < 4 x <1
?
so zeros are at 4 and 1/2 and since this is a parabola facing up it is negative between the zeros.
Lol, idk. Satellite plz correct me
yes of course you are wrong
answer is \[(\frac{1}{2},4)\]
or \[\frac{1}{2}<x<4\] if you prefer
So, x < 4 x <1/2 right?
nope
Then? :S
you have a produce. product is negative when one factor is positive and the other is negative. that is if x is greater than 1/2 and less than 4
what method did u use to factor?
@chelsea eyeball method
(x−4)(2x−1)<0 how will you solve this?
otherwise you can find the zeros using quadratic formula
@saifoo i just did. \[y=(x-4)(2x-1)\] is a parabola facing up. it has zeros at1/2 and 4. so it is negative between them and positive outside. think of the picture (graph)
O, thnks! i was confused b/w 0 & y.
Satellite has figured the correct solution to the equality, not the inequality. The solution is a range of values between but not including 1/2 and 4. Graph the function and see that the part that is below the x-axis represents the solution where f(x) < 0. The answer would be expressed like a <x <b or (a,b). Do you know what a and b are for this problem?
@statman solution is written both ways abut 5 lines or so above
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