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at what points does the curve y= x^3 slope at 45 degrees?
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slope at 45 degrees with the x-axis, right?
yes i think so
the line tangent to the curve must have a slope of 1/2-->the derivative of the x^3=1/2
the derivative of the line tangent to the curve at point a is 1
i don't get it
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is this for calculus?
yes
well, think about it. The slope of line y=x is 45 degrees, and it has a slope of 1
yes
so the derivative of the curve at point a is the slope of the line tangent to the curve at point a = 1
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meaning the derivative of x^3 at a is 1
OHHHHH i understand now thanks ^^
so do u need the solution, or you got it?
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