Any one knows how to solve sin^-1 y = cos y ? (Not using Computer) Mathematically ?
1/sin = cos -> 1= sin cos But cos^2 + Sin^2 = 1 Equate, u have a quadratic in Sin or Cos.
?
I mean Ssin Inverse !
you want \[\arcsin(y)=\cos(y)\] I see no way of doing this without some numerical method
Ah, sorry, thought you meant reciprocal which evidently has no solution (not real ones , anyway).
sure...as \[1=\sin(\theta)\cos(\theta)\] \[\Rightarrow 2=2\sin(\theta)\cos(\theta)\] \[\Rightarrow 2=\sin(2\theta)\] which is a problem since \[-1\leq\sin(2\theta)\leq1\] :)
No,I 'm talking about sin Inverse = Cosine
We know...see my second response.
No That's wrong
what is wrong?
how is sin(x)cos(x)=1 ? For all x ? Just take some values for x as 45 then sin(45)xcos(45)=1/2
see my 2nd response!..not my 3rd which wasn't directed at you
i.e. you want \[\arcsin(y)=\cos(y)\] I see no way of doing this without some numerical method
You see no way of doing it ? Ok !
it is not possible...Mathematica can't even solve it exactly. It only gives a numerical solution
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