Question

Solve for x: (the quad root of)(6x-5)=(the quad root of)(x+10)

Answer 1

Quad it (again).

Answer 2

So would it look like this? (again) \[6^{4}(x)^{4}-5^{4}=x ^{4}+10^{4}?\]

Answer 3

http://www.wolframalpha.com/input/?i=%286x%2B5%29^%281%2F4%29+%3D+%28x%2B10%29^%281%2F4%29

Answer 4

I have told u now 4 times altogether.

6x-5=x+10 so x is 1

Answer 5

6(1)-5=(1)+10

6-5=1+10

1=11?

I don't get you mean by "quad it" quad what?

Answer 6

Sorry

Answer 7

Eve.rything

Answer 8

If u quad the fourth root of 6x-5 u get 6x-5.

Answer 9

If u quad the the fourth root of (x+10) u get x+10

Answer 10

Therefore, for the fifth time

6x-5=x+10 so x is 1

Answer 11

http://www.wolframalpha.com/input/?i=%286x-5%29^1%2F4%3D%28x%2B10%29^1%2F4

Answer 12

5x=15
x=3

Answer 13

HA, HA, AND HA!

Answer 14

JK

Answer 15

Whatever, that's just a computation.

Answer 16

None the less you DID help me find the answer, so thank you! Even though you could've just said that be quading the whole thing it makes the quad root cancel out. Thank you. :)

Answer 17

I did say that, several times, with examples, in the other thread.

Honest:-)

Answer 18

Haha, thanks 8-)