I'm needing help trying to answer 3 problems, can anyone do a videochat with me on this stupid problems
I can maybe help you through twiddla by using graphs and stuff. But first, let me see the question(s) so I can tell you if I'm qualified to help.
this site is full of Helpers! :)
\[\sqrt{2x+4}=\sqrt{x+3}+1\]
Hmm... I do think I can do this. Alright.
I can do this too!
i gott stuck when you square the other side......
the square of 1 is 1.
x = 6
\[\sqrt{2x+4}=\sqrt{x+3}+1\] \[(\sqrt{2x+4})^2=(\sqrt{x+3}+1)^2\] \[2x+4=(\sqrt{x+3}+1)(\sqrt{x+3}+1)\] \[2x+4=(x+3)+2\sqrt{x+3}+1\] \[2x-x+4-3-1=2\sqrt{x+3}\] \[3x=2\sqrt{x+3}\] \[(3x)^2=(\sqrt{x+3})^2\] 9x^2=x+3
oops my 2 disappeared!
nope, itz wrong myininaya
\[9x^2=4(x+3)\]
yes i know my i said my 2 disappeared lol
\[x ^{2} - 4x - 12 = 0\]
ok you are right and i also did 2x+x instead of 2x-x you are right
Which factors to (x-6)(x+2)
We got it all solved in Twiddla. Lol. Great work, dude.
Is there a convention about only taking the positive root? I.e. do we include the x= -2 as a solution?
@Phi: You really go to MIT?
-2 is not a solution since left hand side would not = right hand side sqrt{2(-2)+4}=0 sqrt{-2+3}+1=1+1=2
:O Weird! How did I not catch that when I checked? Thanks, myininaya.
OK, but in the second equation \[\sqrt{-2+3}= \sqrt{1}= \pm1\] So, if we choose -1 we would get -1+1= 0 But I think people only use the positive root??
use only positive the symbol means principal square root (only positive outcome)
Join our real-time social learning platform and learn together with your friends!