Can someone solve the attached problem?

Question

anonymous · Answer

attachment

anonymous · Answer

Ok, well it says solve it by graphing.. so first thing you want to do is be able to graph both lines. Start by putting them into y=mx+b making your first line y=-x+11 and your second will be y=x+5

anonymous · Answer

Go ahead and graph those lines and I do believe you will come up with (3,8)

anonymous · Answer

I do not know how to graph. I was thrown into a math course that was too advanced for me

anonymous · Answer

Ok, no problem.. one sec and I will show you..

anonymous · Answer

thank you

anonymous · Answer

Go ahead and join me here and I'll walk you through it ....... http://www.twiddla.com/584316

anonymous · Answer

I still cant figure out where to put the points since my graph only goes to 11

anonymous · Answer

Is the graph consistent or inconsistent?

anonymous · Answer

well this is a drag.  how to you graph in this stupid system?

anonymous · Answer

answer is easy enough though. add the two equations together to get 
$$2x+6$$
$$x=3$$

anonymous · Answer

then substitute 2 in the first one to get 
$$3+y=11$$
$$y=8$$

anonymous · Answer

so your solution is 
$$x=3,y=8$$

anonymous · Answer

it is "consistent" i guess.