solve the solution by the elimination method 5x+3y=-13 7x-2y=17
sorry,solve the system
wanna cheat?
there are no cheats in math, only more clever methods
Solve for y for both equations. Set y = y. Then solve for x.
answer is \[x=\frac{25}{31},y=-\frac{176}{31}\]
cheating is learning
lol
No it isn't, lol
it is how i learned for sure. we just called it "research"
Hmmm
so im guessing the answer isnt coming from satellite
i sent it already
5x + 3y = - 13 5x = -13-3y x= (-13-3y)/5 7(-13-4y)/5 - 2y = 7 (-91-28y)/5 - 2y = 7 (-91-28y-10y)/5 = 7 (-91-38y) = 35 -38y = 35 + 91 -38y = 126 y = 126/-38 y = -126/38 y = -63/19 5x + 3(-63/19) = -13 5x -189/19 =- 13 (95x - 189)/19 = -13 95x - 189 = -247 95x = -247 + 189 95x = -58 x = -58/95
here it is again. \[x=\frac{25}{31},y=-\frac{176}{31}\]
ordered pair
c'mon. \[(\frac{25}{31},-\frac{176}{31})\]
I'm getting x = 25/31
got it or not cali
I don't know how scientist got his answer
ok one more time \[(\frac{25}{31},-\frac{176}{31})\]
there may be some calculations mistake
I think Cali may have been waiting for more than one person to post the same answer
5x+3y=-137_x-2y=17 Since -2y does not contain the variable to solve for, move it to the right-hand side of the equation by adding 2y to both sides. 5x+3y=-137_x=2y+17 Replace all occurrences of x with the solution found by solving the last equation for x. In this case, the value substituted is 2y+17. 5(2y+17)+3y=-137_x=2y+17 Multiply 5 by each term inside the parentheses. (10y+85)+3y=-137_x=2y+17 Since 10y and 3y are like terms, add 3y to 10y to get 13y. 13y+85=-137_x=2y+17 Since 85 does not contain the variable to solve for, move it to the right-hand side of the equation by subtracting 85 from both sides. 13y=-85-137_x=2y+17 Subtract 137 from -85 to get -222. 13y=-222_x=2y+17 Divide each term in the equation by 13. (13y)/(13)=-(222)/(13)_x=2y+17 Simplify the left-hand side of the equation by canceling the common terms. y=-(222)/(13)_x=2y+17 Replace all occurrences of y with the solution found by solving the last equation for y. In this case, the value substituted is -(222)/(13). y=-(222)/(13)_x=2(-(222)/(13))+17 Multiply 2 by each term inside the parentheses. y=-(222)/(13)_x=-(444)/(13)+17 To add fractions, the denominators must be equal. The denominators can be made equal by finding the least common denominator (LCD). In this case, the LCD is 13. Next, multiply each fraction by a factor of 1 that will create the LCD in each of the fractions. y=-(222)/(13)_x=17*(13)/(13)-(444)/(13) Complete the multiplication to produce a denominator of 13 in each expression. y=-(222)/(13)_x=(221)/(13)-(444)/(13) Combine the numerators of all fractions that have common denominators. y=-(222)/(13)_x=(221-444)/(13) Subtract 444 from 221 to get -223. y=-(222)/(13)_x=(-223)/(13) Move the minus sign from the numerator to the front of the expression. y=-(222)/(13)_x=-(223)/(13) This is the solution to the system of equations. y=-(222)/(13)_x=-(223)/(13)
Scientist!!!
I think your input was wrong
What is 7_x ?
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Scientist...Bagratrix is a fraud
Always give wrong answers
bliss it is not no bliss
it never gives wrong answers
Hold on, let me check...
Yep, it's wrong...x is supposed to be positive, not negative
Look at the second equation...If x is negative, no way you get positive 17 for the answer....sorry
it solved with substitution method
Besides, x is supposed to be a value less than 1. You have something much greater than 1
5x+3y=-13_7x-2y=17 Multiply each equation by the value that makes the coefficients of y equal. This value is found by dividing the least common multiple of the coefficients of y by the current coefficient. In this case, the least common multiple is 6. 2*(5x+3y=-13)_3*(7x-2y=17) Multiply each equation by the value that makes the coefficients of y equal. This value is found by dividing the least common multiple of the coefficients of y by the current coefficient. In this case, the least common multiple is 6. 2*(5x+3y)=2(-13)_3*(7x-2y)=3(17) Multiply 2 by each term inside the parentheses. 2*(5x+3y)=-26_3*(7x-2y)=3(17) Multiply 2 by each term inside the parentheses. (10x+6y)=-26_3*(7x-2y)=3(17) Remove the parentheses around the expression 10x+6y. 10x+6y=-26_3*(7x-2y)=3(17) Multiply 3 by each term inside the parentheses. 10x+6y=-26_3*(7x-2y)=51 Multiply 3 by each term inside the parentheses. 10x+6y=-26_(21x-6y)=51 Remove the parentheses around the expression 21x-6y. 10x+6y=-26_21x-6y=51 Add the two equations together to eliminate y from the system. 21x-6y=51_<U>10x+6y=-26<u>_31x =25 Divide each term in the equation by 31. x=(25)/(31) Substitute the value found for x into the original equation to solve for y. 10((25)/(31))+6y=-26 Multiply 10 by each term inside the parentheses. (250)/(31)+6y=-26 Move all terms not containing y to the right-hand side of the equation. 6y=-(1056)/(31) Divide each term in the equation by 6. y=-(176)/(31) This is the final solution to the independent system of equations. x=(25)/(31)_y=-(176)/(31)
Oh wow, now your answers are magically correct...
got it now bliss it is never wrong before i did it with substitution method but now i did it with addition/elimination method
There's only one way to get it right everytime
good lord what a lot of work.
lol
yes very much
Sometimes a lot of hard work is wasted if the answer is wrong
yes but no problem
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