Question

solve the following second degree equation using the quadratic formula.

a+bx+cx^2=0 ; where c is not equal to zero.

Answer 1

lol...

Answer 2

whts LOL for?

Answer 3

x = \frac{-b \pm \sqrt{b^2 - 4ac}}{2a}

Answer 4

khuram try completing squares ! ; )

Answer 5

\[x = \frac{-b \pm \sqrt{b^2 - 4ac}}{2a}\]

for ax^2 +bx +c so just switch your coefficients about and u r done.

Answer 6

it is lol

Answer 7

It would be different if asked to "derive" the formula itself, however...

Answer 8

If it just says "solve" then u can assume the formula.

Answer 9

sure

Answer 10

the quesiont itself was a joke :P but can't change the coefficients :P

Answer 11

a might be zero?:-)

Answer 12

you are taking it wrong
standard equation is ax^2 +bx +c = 0

and in your equation it is cx^2 +bx +a = 0

Answer 13

yeah i know that standard equation is what you said!

but this question is like cx^2 +bx +a = 0

Answer 14

So swap the coefficients in the formula (and specify a not 0)

Answer 15

so ..the x is now
\[\frac{-b \pm \sqrt{b^2 - 4ac}}{2c}\]

Answer 16

all estudier said was to swap a and c

Answer 17

and maybe you were not able to solve this question ... and when estudier typed lol and me too and all..you felt something different( i don't want it to say ) and now you are kinda covering up (No offence )....I am telling you No Offence ..sorry if it hurts

Answer 18

I didn't mean to cause any offence, please forgive me if i did..

Answer 19

its okay man, i was just confirming my answer.