Question

expand this in binomial theorem:
(x+1)^5

Answer 1

\[(x+a)^{n}=\sum_{k=0}^{n}\left(\begin{matrix}n \\ k\end{matrix}\right)x^{k}a^{n-k}\]

n=5, a=1

Answer 2

So the first term, k=0, will be: \[a^{5}\]

The second, k=1: \[5xa^{4}\]

Answer 3

You continue like this until k=5.

Answer 4

x^5+5x^4+10x^3+10x^2+5x+1