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how do you convert a vector that has something like v=3x-1y into polar coordinates of v=a(r)+b(omega) ?
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x=rcos(theta) y=r sin(theta)
also, r = root(x^2 + y^2)
so, you equation would look something like \[3 r \cos (\theta )-r \sin (\theta )\]
so when i do that equation, x=rcos(theta would i use 3 as my x?
When you see x, replace it with r cos (theta) When you see y, replace it with r sin (theta)
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oh okay
thank you very much
you are welcome
imran, one more question, you couldn't simplify v=2rcos(θ)-3rsin(θ) right? am i not thinking?
you can factor out a 'r' but that does not make much difference r(2 Cos[x]-3 Sin[x])
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alrighty cool. thank you!
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