Question

∫[( 5/x〗 + 6x2 – e^x + x^(1/2))dx

Answer 1

evaluate

Answer 2

one sec let me re write equation

Answer 3

∫[( 5/x〗+ 6x^[2] - e ^[x] + x^(1/2))dx

Answer 4

= ln|5/x| + 2x^3 - e^x + (2/3)*x^(3/2) + C

Answer 5

how did you get 2x^3

Answer 6

the integral of 6x^2 is (6x^3)/3

which simplifies to 2x^3

Answer 7

@agdgdgdgwngo shouldn't it b 5ln|x|? O.o

Answer 8

5lnx +2x^3 - e^x +2/3 x^3/2

Answer 9

right lalay the first one should be 5ln|x|

Answer 10

i am confused so which one is the right integral

Answer 11

lalay's one

Answer 12

lalay is right

Answer 13

isnt there a + c at the end

Answer 14

the antiderivative of 1/x is ln and then you mulltiply that constant back in. And yes there is a +C at the end

Answer 15

yeh forgot the +c ...

Answer 16

cool