Need help again for cal II. Explain why the integral is improper and determine whether it diverges or converges. Evaluate the integral if it converges.

From 3 to 4. 1/(x-3)^(3/2)

Question

Need help again for cal II. Explain why the integral is improper and determine whether it diverges or converges. Evaluate the integral if it converges. 
 
From 3 to 4. 1/(x-3)^(3/2)

anonymous · Answer

you have a zero from 3 to 4 which makes it it non continuous as a function right? someone confirm?

anonymous · Answer

its that the value of function at 3 is undefined. Its ok to have zeros in the interval [a,b]

anonymous · Answer

One of the requirements to be able to integrate a function on an interval [a,b] is that the function is continuous on the interval.

anonymous · Answer

sweet, cal 2 here i come!