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Find the solution set of this inequality. Enter your answer in interval notation using grouping symbols. |-2x+1|<=5
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-2x+1<5 -2x<4 x>2 (2,int) 2x-1<5 2x<6 (3,inf)
i dont get it
wait NO [2,inf) and (-inf,3]
|x|=+x and also -x so you have to solve two systems
i cant put letters tho
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\[|-2x+1|\le5\] First, we remove the absolute value sign by rewriting the equation as follows: \[-2x+1 \le \pm5\] Now we can solve. First solution: \[-2x \le 4\] x > -2 Second solution: \[-2x \le -5\] x > 5/2 Hope this helps: http://www.tutorsean.net
Oops. On the second one, it is x > 3.
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