I need help! simplifying
12x-96/x^2-4x-32 /6x^2-6x-12/3x+3
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OpenStudy (sriram):
plz use the option of equation for long equations
OpenStudy (anonymous):
\[(12x-9)6/(x^2-4x) - 32/(6x^2-6x) -12/(3x+3) ?\]
OpenStudy (anonymous):
error (12x - 96)
OpenStudy (anonymous):
12x-96 over...x^2-4x-32 ..over 6x^2-6x-12/3x+3
OpenStudy (anonymous):
I guess you can solve it like that?
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OpenStudy (anonymous):
is my suggestion correct?
OpenStudy (anonymous):
my options for answeres are...6(x+4)/x-2
orrr.......x+4/6(x-2)....or 6/(x+4)(x-2)....or (x+4)(x-2)/6
OpenStudy (anonymous):
15x^2-4x^3-4x-272/3 if your question at first is right
OpenStudy (anonymous):
thats not even a option
OpenStudy (anonymous):
i dont think my suggestion is correct - the algebra is horrendous and none of those options would fit
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OpenStudy (phi):
\[\frac{12x-96}{x ^{2}-4x-32} \frac{3x+3}{6x^{2}-6x-12}\]
Is this it?? I re-wrote it a bit using
\[\frac{a/b}{c/d}=\frac{a}{b}\frac{d}{c}\]
(Multiply top and bottom by d/c)