Question

Hyperbolas: Question Attached :)

Answer 1

the key is to find the asymptotes for the graph as tho it was centered at the origin; then apply the shifts expressed in the equation for the values of x and y

Answer 2

How do I do that?

Answer 3

first, notice which way the hyper is positioned; the positive side tells you which way the vertexes lie ....

Which value is the positive on this one; x or y?

Answer 4

The x.

Answer 5

good, the hyper splits open left and right then.

the denoms tell us important values for our asymps; the sqrt(25) and the sqrt(9) form the legs of a right triangle

Answer 6

but more importantly, they tell us the "slope" of the line that our asymptotes will take,

namely; sqrt(y denom)/sqrt(x denom) if i recall it correctly

Answer 7

in this case, we have what:

sqrt(9)
------- = the base of the answer, then we have to shift it
sqrt(25)

Answer 8

can you see what the answer will be from that?

Answer 9

The fourth?

Answer 10

i would go with the 4th option :)

Answer 11

thank you for helping :)

Answer 12

youre welcome :)