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OpenStudy (anonymous):
Using half-angle identities, determine:
1. cos(x/2) if tanx = 12/5 and pi < x < 3pi/2
2. in which quadrant
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OpenStudy (anonymous):
tanx = 12/5
p^2 + b^2 = h^2
h= 13
cosx = 5/13
x = (inverse) cos5/13...
OpenStudy (anonymous):
it is 67.38 the x
OpenStudy (anonymous):
but in third quad cos is negative
OpenStudy (anonymous):
so cosx = -5/13
OpenStudy (anonymous):
and third quadrant
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OpenStudy (anonymous):
thanks for the answer but im looking for the exact value of cos(x/2).
I think that using half-angle identities is necessary
OpenStudy (anonymous):
i forgot it is cosx/2 sorry let me do this again
OpenStudy (anonymous):
cosx = -5/13
cos 2* x/2 = 2cos^2 x/2 -1
cosx +1 = 2cos^2 x/2
1 - 5/13 = 2 cos^2 x/2
sqrt(8/(13 *2)) = cosx/2
hers is your answer
and pi<x<3pi/2\
hence pi/2<x < 3pi/4
OpenStudy (anonymous):
which is second quadrant
OpenStudy (anonymous):
whats the basis for finding the quadrant?
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OpenStudy (anonymous):
if it is in quadrant 2, then why is tanx = 12/5 and not negative?
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