Find the missing measures for a right circular cone. r = 3 l = h = 5 L.A. = T.A. = + V =
l = root(h² + r²) = root(5² + 3²) = root(25 + 9) = root(34) so \[l = \sqrt{34}\]
L.A. = πrl so LA = π*3*root(34) = \[3\sqrt{34}\pi\] or 22 LA = --- * 3 * root(34) = 54.97 sq unit 7
T.A. = πrl + πr² (since we have already calculated the value of πrl, we use it here directly) 22 T.A. = 3 root(34) π + π * 3² = 54.97 sq unit + --- * 9 = 54.97 sq unit + 28.29 sq unit 7 = 83.26 sq unit
1 1 22 V = ---- πr²h = --- * --- * 3² * 5 3 3 7 22 * 9 * 5 V = ---------- = 47.14 cubic unit 21
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