Question

can u guys please help me!!! :)
Given the equation x^2+4y^2=16 find:
A)the center C ( use ( , ) )
B)Length of major axis
C)length of minor axis
D)distance from C to foci
Hint: Divide by 6

Answer 1

Step 1) Divide both sides by 16 so the right side becomes 1

Answer 2

So if I remember correctly the center would be (0,0) because it is just x^2 and y^2 not like (x-2)^2 or (y+8)^2

Answer 3

so the center is (0,0)

Answer 4

Step 2) The major and minor axis are the numbers in the denominators of each fraction divided by 2.\[(x ^{2}/16)+(y ^{2}/4) = 1\]

Answer 5

Yep

Answer 6

so major axis would be 16/2 or 8, and minor axis would be 4/2 or 2

Answer 7

Step 3) isn't the foci length of major axis - length of minor axis?

Answer 8

minor

Answer 9

The above might be wrong I believe it is supposed to the square root not divided by 2! so length of major is sqrt(16), and lenght of minor sqrt(4)

Answer 10

so foci location or distance from origin is 4-2?

Answer 11

wow thnxs so much because i dont understand this lesson at all

Answer 12

I don't really remember all of this, but this seems right now. So remember the right side needs to be a 1 and the lengths of the axis are the square root of the denominators.

Answer 13

Good luck!

Answer 14

alright thanks