Is my answer correct? I'm suppose to use rational exponents to write ^4sqrt x * ^5sqrt 3x is this correct? ^20sqrt 3x^9
when you type ^4sqrt do you mean:\[\sqrt[4]{x}\]
\[^4\sqrt x * ^5\sqrt3x\]
ok so what I did first off was change the sqaure roots into fractions so: x^(1/4) * (3x)^(1/5)
the 5 is suppose to be an exponent of the ^5sqrt 3x sorry I cant get it to look like the problem
so it would be (sqrt(3x))^5
which would change to (3x)^(5/2)
so than you would have x^(1/4) * (3x)^(5/2) this probably will help you solve it easier if you change the sqaure roots into fractions.
ok. It still looks confusing to me lol. I feel like I'm learning a foreign language
yep math can seem that way
\[\sqrt[4]{x} *(\sqrt{3x})^{5}\] is this what it looks like?
the first part is right. the second has no () and the ^5 is before the sqrt
I am changing the 4th root into a fraction by taking the number of times the x is under the radical, and dividing that number by the root
\[\left(\sqrt[4]{x}\right)\left(\sqrt[5]{3x}\right)\] \[\left(x^{\frac{1}{4}}\right)\left((3x)^{\frac{1}{5}}\right)\] \[\left(x^{\frac{5}{20}}\right)\left((3x)^{\frac{4}{20}}\right)\] \[\left(x^5\cdot(3x)^4\right)^{\frac{1}{20}}\] \[\left(x^5\cdot81x^4\right)^{\frac{1}{20}}\] \[\left(81x^9\right)^{\frac{1}{20}}\] \[\sqrt[20]{81x^9}\]
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