Question

(1)/(1+(square root of 3)-(square root of 5))

Answer 1

yeah.. it's a bunch of numbers.. then what? lol

Answer 2

\[\frac{1}{1+\sqrt{3}-\sqrt{5}}\]

Answer 3

yes

Answer 4

i need to use the conjugate to rid of the square roots on the denominator

Answer 5

multiply top and bottom by conjugate
conjugate is \[1-(\sqrt{3}-\sqrt{5})\]

Answer 6

well.. the answer is not that easy:

\[[(2\sqrt{3}+1)\sqrt{5}+3\sqrt{3}+7]/11\]

Answer 7

wouldn't it be \[1-\sqrt{3}+\sqrt{5}\]

Answer 8

yes same thing, i just didnt distribute the negative

Answer 9

however after you multiply them you should get
\[-7 +2\sqrt{15}\]
so you have to repeat the process and multiply by its conjugate on top and bottom

Answer 10

can you help by showing the steps, i'm totally getting the wrong answer, i'm making it way too complicated

Answer 11

hey dumb cow pleas ehelp i really need your help

Answer 12

\[\frac{1}{1+\sqrt{3}-\sqrt{5}}*\frac{1-\sqrt{3}+\sqrt{5}}{1-\sqrt{3}+\sqrt{5}} = \frac{1-\sqrt{3}+\sqrt{5}}{1-\sqrt{3}+\sqrt{5}+\sqrt{3}-3+\sqrt{15}-\sqrt{5}+\sqrt{15}-5} = \frac{1-\sqrt{3}+\sqrt{5}}{-7 +2\sqrt{15}}\]

Answer 13

\[=\frac{1-\sqrt{3}+\sqrt{5}}{-7 +2\sqrt{15}}\]

Answer 14

yessss

Answer 15

but i have to work with that conjugate right?

Answer 16

\[\frac{1-\sqrt{3}+\sqrt{5}}{-7 +2\sqrt{15}}*\frac{-7 -2\sqrt{15}}{-7 -2\sqrt{15}}\]

Answer 17

yes

Answer 18

thank you soo much

Answer 19

can you keep going

Answer 20

please