Question

a dragster accelerates to a speed of 112 m/s over a distance of 398 m. determine the acceleration of the dragster. assume uniform acceleration.

Answer 1

we can use eqn of motion...v^2=u^2+2*a*S...assume inital velocity(u) to be zero..then..v=112..and S=398...so u get a=15.759m/s^2

Answer 2

Formula to be used are:

\[a = (V _{f}^{2} +V _{i}^{1} ) \div 2dx\]
\[t= dx/V _{1} + V _{2}\]
Then the given values are:

Initial Velocity= 0
Final Velocity= 112 m/s
Distance= 398
Time=? 3.55 secs

First, we get the time.

Time= 398/ 0+ 112
Time= 3.55 secs

Then we substitute.


a= [(112 m/s^2)- (0^2)] / 2(398 m)
a= 15.75 m/s^2

** note that when squaring a value, the unit of the value must be squared too :)