Question

pls. help me answer this.
Find the derivative
y=x/x^2-1
f(x)=x^2+1/x^2-1

Answer 1

(x^2-1)-2x^2/(x^2-1)^2
-x^2-1/(x^2-1)^2

Answer 2

-4x/(x^2-1)^2 for the second

Answer 3

can you explain how you did it?

Answer 4

1(x^2-1)-2x(x)/(x^2-1)^2

when you do this type of diriv you need to do the following
D(top)*bottom-D(bottom)*top/BOTTOM SQUARED

Answer 5

ok.can you solve this derivative\[\zeta(v)=3-v^2/1+v\]

Answer 6

pls.

Answer 7

sure.
-2v(1+v)-(3-v^2)/(1+v)^2

Answer 8

-2v-v^2-3/(1+v)^2

Answer 9

in our calculus in solving the derivative u and v.
u=the top and v=bottom.are you also using that?

Answer 10

yeah like d(u/v)=u'v-v'u/v^2

Answer 11

its quotient rule right?

Answer 12

the last derivative can you please explain how you did it?

Answer 13

which one?

Answer 14

the last derivative you solved.the ans is \[v^2+2v+3/(3-v^2)^2\]

Answer 15

3-v^2/(1+v)

-2v(1+v)-3+v^2/(1+v)^2
-v^2-2v-3/(1+v)^2

Answer 16

ah.ok thank you very much

Answer 17

am bnut056 pls go to this website http://www.twiddla.com/584540

Answer 18

can you?pls....

Answer 19

hey bnut are you still there?

Answer 20

yeah sorry i was away please write me the question again

Answer 21

can you go to this website pls. http://www.twiddla.com/584540