Question

need to differentiation twice here, y''.

Answer 1

?

Answer 2

this is question:

Answer 3

sorry idk :/

Answer 4

alright, thanks for looking... anyone else can help?

Answer 5

\[2\sqrt y = x-y\]

Answer 6

Ok Lets Differentiate first time

\[\frac{1}{\sqrt y} \frac{dy}{dx} = 1 - \frac{dy}{dx}\]

Answer 7

then

Answer 8

Now Differentiate again

\[-\frac{1}{2 y^3/2} \frac{dy}{dx} + \frac{d^2y}{dx^2} \frac{1}{\sqrt y} = - \frac{d^2y}{dx^2}\]

Answer 9

There Is your Double Differentiate

Answer 10

well it is

\[\Large {-\frac {1}{2y^{ \frac {3}{2} }}\frac{ dy}{dx} } \]

Answer 11

I made a typo there

Answer 12

is that answer = to dy/dx? or is that the final answer as it is..?

Answer 13

No it is the final answer if you want you can have \[\frac{d^2y}{dx^2}\]on one side and have your answer or just let it remain like this