Question

factor the polynomial completely and find all its zeros?
x^5 + 6x^3 + 9x

Answer 1

yikes
\[x(x^4+6x^2+9)\] is a start. then get
\[x(x^2+3)^2\]

Answer 2

pellet is so hard

Answer 3

so i guess the only zero is 0 because
\[x^2+3\] has no zeros

Answer 4

yea a pain but made easier since you can factor out an x at the beginning and end up with a prefect square

Answer 5

very true , thanks for the help