Write the equation of the line that passes by (–1, 4) with a slope of –1 in standard form.
standard form is: ax+by=c ; where slope is defined as -a/b
x + y = c gives us a slope of -1/1 = -1 use the point to calibrate for c
So It Would Be A(-1)+B(4)=3 ?
x+y=3
x + y = c (-1) + (4) = c 3 = c x+y = 3
So What's The Standform Of The Equation ?
Standard Form*
you want to set up the equation like this. (y-y1)=m(x-x1) where x1,y1 are your given coordinates. and m is they slope. so you just plug and chug
i would assume it is the equation which we gave you and worked out for you ...
y-(4) =-1(x-(-1)) y-4=-x-1 y=-x+3 that is the line of the equation
Well Its Not . . Nevermind Someone Else Gave Me The RIGHT Answer
hope that helped...?
It Did Thanks :D
http://www.mathwords.com/s/standard_form_for_the_equation_of_a_line.htm then you should complain to whoever wrote your question :)
The standard equation of line is Ax+By=C, here A=B=1,C=3 therefore 1x+1y=3 is the standard equation
slope intercept form of a line is: y = -x + 3
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