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Solve the differential equation. f '(x) = 8x, f(0) = 3
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Take the integral of f'(x) giving you \[f(x)=4x^2+C\]then substitute in the given values for x and f(x) \[3=4(0)^2+C\]\[3=C\]this gives you\[f(x)=4x^2+3\]
Find a function f that satisfies the conditions. f ''(x) = x2, f '(0) = 4, f(0) = 8
x^2*
could you help me with this please
same thing as before except now you have to solve for two unknowns, integrate once, find the first unknown, integrate the answer for get for f'(x) and find the second unknown using the information given.
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