Question

Airplane A travels 1400 km at a certain speed. Plane B travels 1000 km at a speed 50 km/h faster than plane A in 3 hrs less time. Find the speed of each plane.

Answer 1

I used to hate these..now they're my favorite...

Answer 2

Are you there?

Answer 3

I am here. I usually can figure these out, but having trouble with this one.

Answer 4

I see....sorry for taking so long...would you like me to post a classroom and show you?

Answer 5

The only part that I saw was "Report Abuse". Did you copy this from somewhere else? lol

Answer 6

No disrespect Duke, but I was going to show nettej94 a much easier way to solve it that would involve less confusion.

Answer 7

Yes, I know Duke.

Answer 8

let da = 1400 km
let Va = speed of plane A
let ta = time a

let Vb = speed of plane B
let db = 1000 km
let tb = time b

db = Vb*tb
1000 km = (Va + 50 km/h)(da/Va - 3h)
1000 km = (Va + 50 km/h)(1400km/Va - 3h)

now solve for Va
add 50 km/h to get Vb

oh a relationship between da, Va and ta may be helpful
da = Va*ta
db = Vb*tb

Answer 9

I did copy it from somewhere else.

Answer 10

open study glitchy right now on my CPU. I post then go back and see nothing
I did copy my work from a page that I posted the answer
remember many ways to solve this problem if it was originally a physics problem

Answer 11

going to log out and shut down
maybe site will work for me tomorrow

Answer 12

I used to have those kinds of problems with OS....not anymore...

Answer 13

A: r t = d, r = d/t, r=1400/t
B: (r + 50) (t - 3) =1000
Replace r in the above equation with 1400/t and solve for t.
t = -12 and 7. Use t = 7 and solve r=1400/t for r. r = 200
A: r = 200 mph
B: r + 50 = 250 mph
Verify B:'s equation:
(200 + 50)(7 - 3) = 1000 ?
1000 = 1000 yes