Write the slope intercept equation for the line containing the given pair of points..(-3,4) and (3,1).... Please HELP ME ANYONE
1. Find Slope 2. Use Point-Slope Formula 3. Simplify
I dont know the formula
slope = m m= (y2-y1)/(x2-x1)
yep, than plug m in: y-y1= m(x-x1) to find eq.....
can you show me where each number goes and I will do the rest I get confused with which is the y-y1 and the x-x1.
Trust, it must still be early where you're at.
Usa,
I live in the carolinas
Then that means it's very early.
and very late
like 3am here where you at in the world. and what is the time there
x1 and y1 is from one of your two given points. (-3,4) = (x1,y1) & (3,1)= (x2,y2). What did u get for slope m?
yes 1/2 but where do I go next
You should get -1/2 for m...?
Late as ever.
i did what is next
Now, use eq: y-y1=m(x-x1) to find slope eq.
You could use either points, both will give u the same answer.
ok how do i start
Just plug in y1 and x1 in the eq. and solve using algebra.
so -3=-1/2(4)+b
I believe you using the other eq. "y=mx+b" b is your y-intercept on the graph (if u graphed it). You are not trying to find b but instead an equation of a line in that form. Use this my friend: y-y1= m(x-x1) * You know m * You know y1, x1 * Plug and chug.
so it would be 5=1/2(6)
3=1/2(6)
Uhmm, not quite: y-y1= m(x-x1) Lets do the first point: (-3,4) ---> (x1, y1) Plug in what u know: y1= 4, x1=-3, m=-1/2 y-4= (-1/2)(x-(-3)) From here, solve...
um -4=-1-1... i dont know I hate math. ugh
will you please write out everything foe me i am already gonna give you the medal please with cherries on top.
you dont do anything with y and x. at the end, u should have something like y= ?x + ?
i will simplify u one more step to see if u could finish it by yourself: y-4= (-1/2)(x-(-3)) y-4=-.5x -1.5 easier now? solve
oh I think I got it now y=1/2x+5/2
yes cept your slope (m) is -.5. if u plug in the other point, you will have the same answer. your 5/2 is your y intercept. if u wanna see, plug 0 for x.
o okay is now thank you
your welcome. bye bye
bye
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