solve for x using quadratic formula x2+10x=9
how about this? \[x^2+10x=9\] \[(x+5)^2=9+5^2\] \[(x+5)^2=34\] \[x+5=\pm\sqrt{34}\] \[x=-5\pm\sqrt{34}\]
quadratic formula is harder to use here because it forces you to have a denominator. if the "middle term" has an even coefficient it is much easier to complete the square, which is really all the formula does for you anyway
first you would have to write \[x^2+10x-9=0\] then use \[x=\frac{-b\pm\sqrt{b^2-4ac}}{2a}\] with \[a=1,b=10,=-9\] you would get \[x=\frac{-10\pm\sqrt{136}}{2}\] and then you would have to simpify
simpify please
i did
when you simplify you get \[x=-5\pm\sqrt{34}\]
ok
oh you mean how how do you simplify \[x=\frac{-10\pm\sqrt{136}}{2}\]?
ya
i can show you if you like. you will get \[-5\pm\sqrt{34}\] but you have to be careful
ok
first of all you have to take care of \[\sqrt{136}\] is it \[\sqrt{4\times 34}=2\sqrt{34}\] because the square root of 4 is 2
then you have \[\frac{-10\pm2\sqrt{34}}{2}\] factor out a 2 to get \[\frac{2(-5\pm\sqrt{34}}{2}\] then cancel to get \[-5\pm\sqrt{34}\]
you can see why completing the square is easier here
ya
i don't have to do all that simplification at the end. get the answer in 4 easy steps
thanks
you can see the four steps at the top of this post. they are simpler than all this quadratic formula mes
yw
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