Question

Lost in the algebra for this problem

Answer 1

Ill be posting it in one sec, sry.

Answer 2

how would you simply this
\[(5/x -2) -2 ALL OVER 5\]

Answer 3

thats all over 5 by the way

Answer 4

\[\frac{5}{x-2} -2 \over 5\]

I would start by multiplying the top and bottom by (x-2) to get rid of the complex fraction.

Answer 5

So multiply your fraction by 1 at it will be the same thing. Anything over itself is 1 so we have: \[{\frac{5}{x-2} -2 \over 5} = {\frac{5}{x-2} -2 \over 5} \cdot \frac{x-2}{x-2} = ?\]

Answer 6

o I see. all i needed was that starting point, thanks

Answer 7

Whenever you have a complex fraction, multiply the top and bottom of the 'outer' fraction by the LCD of all the 'inner' fractions.

Answer 8

It'll simplify things nicely.

Answer 9

thx