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3(y+4)-10=66-5y
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\[3y+12-10=66-5y\]
You start by distributing that 3 to each of the terms in parens.
6y+2=66-8y?
3y + 2 = 66 - 8y
I dunno how you got an extra factor of 2 on the front there.
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because it said 12-10
Right, but that doesn't affect the 3y part.
3(y+4) = 3y +3(4) = 3y + 12
you said multiply both parts by3 n i did that. then did 12-10
Somehow you got a 6y instead of the 3y
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Yes, that was right. The 6y was the part that was wrong.
\[3y+2=66-5y\] now add 5y and subtract 2 on both sides \[3y+2+5y-2=66-5y+5y-2\]
Or do it as separate steps if you don't follow that.
8y=66-10?
8y = 66 - 2
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8y = 64 now divide 8 on both sides \[8y/8 = 64/8\]
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