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Mathematics 21 Online
OpenStudy (anonymous):

3(y+4)-10=66-5y

OpenStudy (anonymous):

\[3y+12-10=66-5y\]

OpenStudy (anonymous):

You start by distributing that 3 to each of the terms in parens.

OpenStudy (anonymous):

6y+2=66-8y?

OpenStudy (anonymous):

3y + 2 = 66 - 8y

OpenStudy (anonymous):

I dunno how you got an extra factor of 2 on the front there.

OpenStudy (anonymous):

because it said 12-10

OpenStudy (anonymous):

Right, but that doesn't affect the 3y part.

OpenStudy (anonymous):

3(y+4) = 3y +3(4) = 3y + 12

OpenStudy (anonymous):

you said multiply both parts by3 n i did that. then did 12-10

OpenStudy (anonymous):

Somehow you got a 6y instead of the 3y

OpenStudy (anonymous):

Yes, that was right. The 6y was the part that was wrong.

OpenStudy (anonymous):

\[3y+2=66-5y\] now add 5y and subtract 2 on both sides \[3y+2+5y-2=66-5y+5y-2\]

OpenStudy (anonymous):

Or do it as separate steps if you don't follow that.

OpenStudy (anonymous):

8y=66-10?

OpenStudy (anonymous):

8y = 66 - 2

OpenStudy (anonymous):

8y = 64 now divide 8 on both sides \[8y/8 = 64/8\]

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